A simple pendulum consists of a brass sphere of mass m = 1 kg suspended on a string of length L 1 meter. The pendulum oscillates with amplitude A = 1 cm and period T = 2 seconds. Which of the following alterations will change the period of the pendulum’s oscil- lations to T′ = 1 second?

1. Using a shorter string of length L' ˜ 0.5meters.
2. Reducing the oscillation amplitude to A' =0.25cm
3. Using a heavier brass sphere of mass m' ˜ 4Kg.
4. Increasing the oscillation amplitude to A' =4cm.
5. Using a longer string of length L' ˜ 2meters
6.Using a shorter string of length L' ˜ 0.25meters
7. Using a longer string of length L' ˜ 4 meters
8. Using a lighter brass sphere of mass m' ˜ 0.25Kg.

d₁ = displacement of tern from arctic to antarctic = 11000 miles

d₂ = displacement of tern from antarctic to arctic =   - 11000 miles

d = total displacement for the journey

total displacement for the journey is given as

d = d₁ + d₂

d = 11000 + (-11000)

d = 0 miles

t₁ = time of travel from arctic to antarctic = 3 months = 3 x 30 days = 90 days

t₂ = time of travel from antarctic to arctic = 3 months = 3 x 30 days = 90 days

t = total time of travel

total time of travel is given as

t = t₁ + t₂

t = 90 + 90

t = 180 days

average velocity is given as

average velocity = total displacement/ total time

v = d/t

v = 0/180

v = 0 miles/day

that tool is called an altimeter which measures your altitude which can be used to tell which atmosphere you are currently in, including the stratosphere.

hope this ! : )

attach the statements so i can answer : )