A centripetal force of 190 N acts on a 1,550-kg satellite moving with a speed of 5,300 m/s in a circular orbit around a planet. What is the radius of its orbit?

Radius, r is equal to 229.16×10^6m

Explanation:

Given the following parameters;

Centripetal force on the satellite, Fc = 190N.

Mass of the satellite, M = 1,550-kg.

Speed of the satellite, V = 5,300m/s.

The relationship between a satellite of mass (m) moving in a circular orbit of radius (r) with a speed (v) and a centripetal force (Fc) is given by the equation;

Fc = (MV²)/r

Since, we're solving radius, r; we make "r" the subject of formula;

Thus, r = (MV²)/Fc

Substituting into the above equation;

r = (1550 × [5300]²)/190

r = (1550 × 28090000)/190

r = 43539500000/190

r = 229155263.16

Radius, r is equal to 229.16 × 10^6m

get the total number of pieces of fruit and divide it by 4 to get the average. the result is the answer to the problem. 14 total number of fruits and there are 4 members. 14 divided by 4 is equals to 3.5.