An apple falls out of a tree from a height of 2.3 m What is the impact speed of the apple?

6.72 m/s

Explanation:

recall that the equations of motion may be expressed as

v² = u² + 2as

where,

v = final velocity,

u = initial velocity = 0 m/s because it is stationary before it starts falling

a = acceleration (in this case because it is falling, it is the acceleration due to gravity = 9.81 m/s²)

s = distance traveled = 2.3m

in our case, if we neglect air resistance, then we simply substitute the known values above into the equation of motion.

v² = u² + 2as

v² = 0² + 2(9.81)(2.3)

v² = 45.126

v = √45.126

v = 6.72 m/s