When a falling meteoroid is at a distance above the Earth's surface of 3.50 times the Earth's radius, what is its acceleration due to the Earth's gravitation?

0.484 m/s²

Explanation:

To solve this question, we would apply the formula for calculating gravitational acceleration at any distance.

g = GM/r², where

g = acceleration due to gravity

G = gravitational constant

r = radius of the meteoroid

Radius of the earth is given as 6371 km

The meteoroid is located at a distance 3.5 times the radius of the earth, so

r = R + 3.5R = 4.5R

r = 28670 km

Mass of the earth is, 5.97*10^24 kg

Now, we proceed to substitute our values into the earlier equation

g = GM/r²

g = (6.67*10^-11 * 5.97*10^24) / 28670²

g = 398.2*10^12 / 822*10^12

g = 0.484 m/s²

Thus, it's acceleration due to earth's gravitation is 0.484 m/s²

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