A rod has length 0.900 mm and mass 0.500 kgkg and is pivoted at one end. The rod is not uniform; the center of mass of the rod is not at its center but is 0.500 mm from the pivot. The period of the rod's motion as a pendulum is 1.49 ss. What is the moment of inertia of the rod around the pivot
Answers: 1
is the moment of inertia about the pivot so making ![I = [\frac{T}{2\pi } ]^2 * m * g * d](/tpl/images/0712/7139/dddf6.png)
![I = [\frac{1.49}{2* 3.142 } ]^2 * 0.5 * 9.8 * 0.5](/tpl/images/0712/7139/222dd.png)
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A rod has length 0.900 mm and mass 0.500 kgkg and is pivoted at one end. The rod is not uniform; the...
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