A 19.5-cm-diameter loop of wire is initially oriented perpendicular to a 1.8-T magnetic field. The loop is rotated so that its plane is parallel to the field direction in 0.22 s . Required:
What is the average induced emf in the loop?

Given that,

Diameter of the loop, d = 19.5 cm

Magnetic field, B = 1.8 T

The loop is rotated so that its plane is parallel to the field direction in 0.22 s. We need to find the average induced emf in the loop.

When it is placed perpendicular to the magnetic field, angle between Area vector and Magnetic Field will be 0. Flus is BA.

When it is rotated so that its plane is parallel to the field direction, angle between Area vector and Magnetic Field will be 90. Flus is 0.

The induced emf is given by :

So, the average induced emf in the loop is 2443.48 volts.

what was the acceleration of the 2 kg cart?

⇒ 16.0 cm/s2

what was the acceleration of the 4 kg cart?

⇒ 8.1 cm/s2

what was the acceleration of the 6 kg cart?

⇒ 5.3 cm/s2

d₁ = displacement of tern from arctic to antarctic = 11000 miles

d₂ = displacement of tern from antarctic to arctic =   - 11000 miles

d = total displacement for the journey

total displacement for the journey is given as

d = d₁ + d₂

d = 11000 + (-11000)

d = 0 miles

t₁ = time of travel from arctic to antarctic = 3 months = 3 x 30 days = 90 days

t₂ = time of travel from antarctic to arctic = 3 months = 3 x 30 days = 90 days

t = total time of travel

total time of travel is given as

t = t₁ + t₂

t = 90 + 90

t = 180 days

average velocity is given as

average velocity = total displacement/ total time

v = d/t

v = 0/180

v = 0 miles/day