Two asteroids identical to those above collide at right angles and stick together; i. e, their initial velocities were perpendicular to each other (take A initially moving to the right and B initially moving up). Use momentum conservation (make a complete Momentum Chart) to find the velocity (magnitude and direction with-respect-to the velocity asteroid A had before the collision) of the asteroids after the collision.

velocity = 62.89 m/s  in 58 degree measured from the x-axis

Explanation:

Relevant information:

Before the collision, asteroid A of mass 1,000 kg moved at 100 m/s, and asteroid B of mass 2,000 kg moved at 80 m/s.

Two asteroids moving with velocities collide at right angles and stick together. Asteroid A initially moving to right direction and asteroid B initially move in the upward direction.

Before collision Momentum of A = 1000 x 100 = kg - m/s in the right direction.

Before collision Momentum of B = 2000 x 80 = 1.6 x  kg - m/s in upward direction.

Mass of System of after collision = 1000 + 2000 = 3000 kg

Now applying the Momentum Conservation, we get

Initial momentum in right direction = final momentum in right direction =

And, Initial momentum in upward direction = Final momentum in upward direction = 1.6 x

So,  =  m/s

and  m/s

Therefore, velocity is =

                                   =

                                   = 62.89 m/s

And direction is

tan θ =     = 1.6

therefore,

                   =  from x-axis

the ima (higher than 1m) will be greater than the ima with the height of 1m.