The flight path of a jet aircraft as it takes off is defined by the parmetric equations x=1.25 t2 and y=0.03 t3, where t is the time after take-off, measured in seconds, and x and y are given in meters. If the plane starts to level off at t = 40 s, determine at this instant:a. The horizontal distance it is from the airport b. Its altitudec. Its speed.

A. We are given t= 40s, x=1.25t²

So The horizontal distance it is from the airport will be = 1.25(40)²= 2000meters

B. y= 0.03t³

So y= 0.03(40)³= 1920m altitude

C. To find speed

We say

dx/dt=Vx= 2.5t= 100

dy/dy = 0.09t= 144

So speed= √100²+144²= 175.31m/s

when jerome paddle in flowing river towards east the net speed of jerome will increase

so the net speed of jerome will be given as

now the speed of paul will be same as it is given as he is running on the ground

so

so here we can say since the speed of jerome is more so he will win the race

now as we know the distance so the time difference is given as

so jerome will reach first and the time difference will be 203.55 s or 3.4 min