Suppose A=BnCm, where A has dimensions LT, B has dimensions L2T-1, and C has dimensions LT2. Then the exponents n and m have the values?A. 2; 3B. 2/3; 1/3C. 4/5; -1/5D. 1/2; 1/2E. 1/5; 3/5

The values of the exponents n and m are and respectively.

The given parameters;

The values of the given exponents "n" and "m" are calculated as follows;

from equation(2);

substitute the value of n into equation (1);

Thus, the values of the exponents n and m are and respectively.

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Explanation:

The expression is :

A =[LT], B=[L²T⁻¹], C=[LT²]

Using dimensional of A, B and C in above formula. So,

Comparing the powers both sides,

2n+m=1 ...(1)

2m-n=1 ...(2)

Now, solving equation (1) and (2) we get :

Hence, the correct option is (E).

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