An object initially at rest breaks into two pieces as the result of an explosion. one piece has twice the energy of the other piece. what is the ratio of the masses of the two pieces? which piece has the larger mass?

M₁V₁ = m₂V₂ 
KE = ½mV² 
½m₁V₁² = 2*½m₂V₂² 

m₁V₁ = m₂V₂ 
½m₁V₁² = m₂V₂² 

m₁/m₂ = V₂/V₁ 

m₁/m₂ = 2V₂²/V₁² 
V₂/V₁ = √(½m₁/m₂) 

m₁/m₂ = √(½m₁/m₂) 
squaring
(m₁/m₂)² = ½m₁/m₂ 

2m₂m₁² = m₁m₂² 
divide by m₁m₂ 
2m₁ = m₂ 
m₂/m₁ = 2 
hope this helps

This is what i found on google “according to the collision theory, the following criteria must be met in order for a chemical reaction to occur: molecules must collide with sufficient energy, known as the activation energy, so that chemical bonds can break. molecules must collide with the proper orientation.” i hope this information you.

Since you have not included the experiment situation and the data, of course, i can not give you specific details about it. but i can you with this question.1) i will assume that the motion is projectile (parabolic) motion.2) yes, the horizontal distance depends on the horizontal velocity as, naming vx the horizontal velocity and t the time, it is: x = vx × t3) now, observe that the flight time depends on the vertical velocity as, naming voy the initial vertical velocity, t the time and y the vertical distance before reaching the ground: y = yo + voy×t - gt² / 2.the higher the initial vertical velocity (voy) the longer the object will be flying and so t will be higher in the equation for the horizontal distance.that explains the relationship between the horizontal distance and the horizontal velocity.