Please help meee Three charges are on the y-axis. One positive charge, q1 = 9.0 μC, is at y = 3.0 m. A second charge of −19 μC is located at the origin. A third charge of 9.0 μC is placed so that q2 is in electrostatic equilibrium with q1 and q3. How large must the electrostatic force between q2 and q3 be to balance the force between q1 and q3?

gpe = mass x gravity constant x height or… gpe = mgh

where… mass: measured in kilograms (kg)

gravity: gravity constant on earth = 10.00 m/s2

height: measured in meters (m)

gpe: measured in joules (j) or kilojoules (kj)

how do you solve gpe?

gravitational potential energy (gpe) is the energy an object has because of its position above the. ground.

gpe = mass x gravity constant x height or… gpe = mgh.

mass:

note: to earn full marks when solving science word problems, you must show your work:

formula.

example:

given values:

mass = 0.3 kg.

a=d/t

a="triangle"v/t

explanation:

a = acceleration

electrical potential energy =0.072 j

explanation:

electrical potential energy is given by

u= q δv

q= charge=6 c

δv= potential difference and is given by

δv= e d

e= electric field

d= distance=5 mm=0.005 m

δv=2.4 (0.005)=0.012 v

now electric potential energy= u= q δv

u=6 (0.012)

u=0.072 j