Compute the torque (in m-N) applied by a hanging mass of 105.7 g at 37.8 cm away from the axle. The torque is applied perpendicularly to the radius.

The torque applied perpendicularly to the radius is 0.392 N.m.

Explanation:

Given;

mass of the axle, m = 105.7 g = 0.1057 kg

radius of the axle, r = 37.8 cm = 0.378 m

The torque applied perpendicularly to the radius is given by;

τ = F x r

τ = mg x r

τ = (0.1057 x 9.8) x 0.378

τ = 0.392 N.m

Therefore, the torque applied perpendicularly to the radius is 0.392 N.m.

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