A cannon is fired horizontally from the edge of a small cliff. The height of the cliff is 104.0 m. The cannon ball is fired with a perfectly horizontal velocity of 24.6 m/s and it took 2.3s to reach the ground. How far will the cannon ball fly horizontally before it strikes the ground?

h = 134.65 m

Explanation:

It is given that,

The height of the cliff is 104.0 m, h₀ = 104 m

Initial horizontal velocity of the ball, u = 24.6 m/s

It takes 2.3 s to reach the ground, t = 2.3 s

We need to find how far will the cannon ball fly horizontally before it strikes the ground. let it is h. Using second equation of motion as follows :

Here, a = -g

So,

So, the cannonball will cover a distance of 134.65 m before it strikes the ground.

positive reinforcement? ?

graphing motion: mastery test

209be

what is the instantaneous acceleration of

the particle at point b?

0 meters/second?

10 meters/second?

12 meters/second?

velocity imetersisecond

15 meters/second?

20

time (seconds)

answer: 0 meters/second^2