Una espira plana de alambre formada por una sola vuelta de 8.00 cm2 de área de sección transversal es perpendicular a un campo magnético que aumenta uniformemente de magnitud de 0.500 T a 2.50 T en 1.00 s. ¿Cuál es la corriente inducida resultante si la espira tiene una resistencia de 2Ω

Explanation:

Given that,

Cross-sectional area, A = 8 cm² = 0.0008 m²

The initial magnetic field,

The final magnetic field,

Time, t = 1 s

The resistance of the loop, R = 2 Ω

We need to find the induced current. Due to the change in the magnetic field, emf will include in the loop. The induced emf is given by :

Let I is the induced current. Using Ohm's law,

V = IR

So, the induced current in the loop is .

dec 23, 2016 - a load of bricks weighing 680 n a distance of 10 m across a parking lot. if if the worker pushes the cart with a constant force of 209 n, what work= force x distance = 220 n x 10 m = 2200 n.m = 2200 j i don't know where the person got it from, but the initial part, work= force x distance me.