A block of mass m = 4.80 kg is suspended as shown in the diagram below. Assume the pulley to be frictionless and the mass of the strings to be negligible. If the system is in equilibrium, what will be the reading of the spring scale in newtons?

W = 47.04 N

Explanation:

It is given that,

A block of mass 4.8 kg is suspended by the pulley and it is assumed that it is frictionless and the mass of the strings to be negligible.

We need to find the reading of the spring scale if the system is in equilibrium.

At this position, the scale reading is equal to the weight of the block such that,

W = mg, where g is the acceleration due to gravity

W = 4.8 kg × 9.8 m/s²

W = 47.04 N

So, the reading of the spring scale is 47.04 N.

the bal will not change its velocity.

answer: 2×10^-2kg

explanation: density= mass per volume

vol=mass/density

converting to s.i units we have;

3÷1000kg = 0.003

1.5÷100m = 0.15

0.003/0.15 = 0.02kg