A ball is thrown up with a speed of 15m/s. How high will it go before it begins to fall? ( g = 10m/s2 )

Height is 11.25m

Explanation:

Given the following data;

Initial velocity, u = 0

Final velocity, v = 15m/s

Acceleration due to gravity, g = 10m/s²

To find the height, we would use the third equation of motion;

Where;

Making S the subject, we have;

But a = g = 10m/s²

Substituting into the equation, we have;

S = 11.25m

Therefore, the ball will reach a height of 11.25m before it begins to fall.

the answer is 12 as i may remember

: )