MARKING BRAINLIEST: A 75.0 kg person rides up and down in an elevator that starts from rest, accelerates from rest to 2.0m/s in 2.0s, continues at a constant velocity of 2.0m/s for 2.0s, and then comes to a stop from 2.0m/s in 2.0s. Calculate what the scale would read in each of the following situations. Show all work including free-body diagrams. Round off g to 10 m/s2.

trig 15.3 cos

truck y has a greater velocity than truck x.

the minimum constant speed at which she can catch the train is 2.7 m/s

given:

acceleration = 0.6

time = 4.5 s

to find:

velocity = ?

formula used:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

solution:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

v = 0 + (0.6 × 4.5)

v = 2.7 m/s

the minimum constant speed at which she can catch the train is 2.7 m/s