An object is launched with an initial speed of 30 m/s at an angle of 60° above the horizontal . What is the maximum height reached by the object

H = 34.43 m

Explanation:

Given that,

Initial speed of the object, u = 30 m/s

The angle of projection,

We need to find the maximum height reached by the object. Let it is H. Using the formula for maximum height reached by the projectile.

So, the maximum height reached by the object is 34.43 m.

t = 1/400 h   ⇔ 0.0025 h ⇔ 9s ⇔ 0.15 m

any of the answers are correct.

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