Two jupiter-size planets are released from rest 1.40×10^11 m apart.. what are their speeds as they crash together?

M₁ = mass of planet #1 
M₂ = mass of planet #2 
M = total mass 
R₁ = radius of planet #1 
R₂ = radius of planet #2 
d₁ = initial distance between planet centers 
d₂ = final distance between planet centers 
a = semimajor axis of plunge orbit 
v₁ = relative speed of approach at distance d₁ 
v₂ = relative speed of approach at distance d₂ 

M₁ = M₂ = 1.8986e27 kilograms 
M = M₁ + M₂ = 3.7972e27 kg 
G = 6.6742e-11 m³ kg⁻¹ sec⁻² 
GM = 2.5343e17 m³ sec⁻² 
d₁ = 1.4e11 meters 
a = d₁/2 = 7e10 meters 
R₁ = R₂ = 7.1492e7 meters 
d₂ = R₁ + R₂ = 1.42984e8 meters 
v₁ = 0 
v₂ = √[GM(2/d₂−1/a)] 

v₂ = 59508.4 m/s 

The time to fall is 1337.7 days

.I hope my answer has come to your help. Thank you for posting your question here in .

3is a crest4 is a trough 2 is the amplitude 1 is the wavelength