A two-stage rocket accelerates from rest at +3.57 m/s/s for 6.82 seconds. It then

accelerates at +2.98 m/s/s for another 5.90 seconds. After the second stage, it enters

into a state of free fall. Determine:

a. the maximum speed

b. the maximum altitude

c. the height of the rocket after 20.0 seconds

d. the total time the rocket is in the air (assuming it is launched from the ground)

the answer is a 3.8cm

explanation:

the minimum constant speed at which she can catch the train is 2.7 m/s

given:

acceleration = 0.6

time = 4.5 s

to find:

velocity = ?

formula used:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

solution:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

v = 0 + (0.6 × 4.5)

v = 2.7 m/s

the minimum constant speed at which she can catch the train is 2.7 m/s