A box is sitting stationary on a long level ramp on level ground. The coefficient of static friction is (1.0). One end of the ramp is slowly lifted higher and higher. What is the angle of the ramp with respect to the ground when the box begins slidig?

45 degrees

Explanation:

Given that the coefficient of friction,

Let the angle of the ramp be .

The gravitational force acting downward

The normal reaction by the ramp on the box,

So, the maximum frictional force that can act on the box,

The force along with the plane in the direction of sliding,

When the box begins sliding, the F must have to overcome the frictional force,f.

So, F=f

Putting the value of \mu, we have

degrees.

Hence, the angle of the ramp with respect to the ground when the box begins sliding is 45 degrees.

r = ρ x length / area  

ρ = r x area / length  

ρ is in ohm-meters  

in basic units, it is m³kg/s³a²  

i think this is it.

there are no contact forces mentioned on the list of choices that you've provided.