Two football players have the same momentum. One player with a mass of 100 kg is moving at a velocity of 4 m/s. If the second player is moving with a speed of 5.5 m/s, what must his mass be

The mass of the second player is 72.73 kg

Explanation:

Given;

mass of the first player, m₁ = 100 kg

velocity of the first player, u₁ = 4 m/s

velocity of the second player, u₂ = 5.5 m/s

let the mass of the second player = m₂

Since they have equal momentum, the mass of the second player will be obtained by equating their momentum.

m₁u₂ = m₂u₂

100 x 4 = 5.5m₂

400 = 5.5m₂

m₂ = 400 / 5.5

m₂ = 72.73 kg

Therefore, the mass of the second player is 72.73 kg

the answer is f1 and d2 because if you put equal force on those two points the beam would balance trust me on this

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