Physics, 13.01.2021 14:00 joannachavez12345

Mathematically, explain how a car (A) with mass of 500 kg and velocity of 2 m/s has the same kinetic energy as a car (B) with mass of 20000 g and velocity of 10 m/s.

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Answer from: nathanbrockdac

The calculated kinetic energy values of the cars are the same. The kinetic energy is 1000 J for each of the cars.

Then, we can conclude that, car (A) with mass 500 kg and velocity of 2 m/s has the same kinetic energy as a car (B) with mass of 20000 g and velocity of 10 m/s.

Kinetic energy can be calculated using the formula

$K.E = \frac{1}{2} mv^{2}$

Where K.E is the kinetic energy

m is the mass

and v is the velocity

For car (A)

m = 500 kg

and v = 2 m/s

Then,

$K.E_{(A)} = \frac{1}{2} \times 500 \times 2^{2}$

$K.E_{(A)} = \frac{1}{2} \times 500 \times4$

$K.E_{(A)} = 1000 \ J$

For car (B)

m = 20000 g = 20 kg

v = 10 m/s

Then,

$K.E_{(B)} = \frac{1}{2} \times 20 \times 10^{2}$

$K.E_{(B)} = \frac{1}{2} \times 20 \times 100$

$K.E_{(B)} =1000 \ J$

From above, we can observe that the calculated kinetic energy values of the cars are the same.

Hence, car (A) with mass 500 kg and velocity of 2 m/s has the same kinetic energy as a car (B) with mass of 20000 g and velocity of 10 m/s.

Learn more on calculating kinetic energy here: link

Answer from: patrickfutrell2537

Both kinetic energies are equal

Explanation:

Kinetic Energy

Is the type of energy of an object due to its state of motion. It's proportional to the mass and the square of the speed.

The equation for the kinetic energy is:

$\displaystyle K=\frac{1}{2}mv^2$

Where:

m = mass of the object

v = speed of the object

The kinetic energy is expressed in Joules (J)

There are two cars:

Car (A) with mass ma=500 kg and speed va= 2 m/s

Car (B) with mass mb=20,000 gr and speed vb= 10 m/s

Calculate the kinetic energy of both cars:

$\displaystyle K_a=\frac{1}{2}m_av_a^2$

$\displaystyle K_a=\frac{1}{2}500*2^2$

$\displaystyle K_a=250*4=1,000 J$

To calculate the Kb, the mass must be expressed in kg:

mb=20,000/1,000 =20 Kg

$\displaystyle K_b=\frac{1}{2}m_bv_b^2$

$\displaystyle K_b=\frac{1}{2}20*10^2$

$\displaystyle K_b=10*100=1,000 J$

Both kinetic energies are equal

Answer from: Quest

radiation warms things up temp rises convection currents air circ windy weather

Answer from: Quest

answer: at 24 february, 2014 the population gets twice of its initial population.

explanation:

since we have given that

the population for alpha city, t years after january 1, 2004 is given as

$p(t)=0.3t^2+6t+80$

first we find out the initial population, i.e. t=0,

so, our quadratic equation becomes,

$p(0)=0+0+80=80$

according to question, we have said that if the population has twice its initial population, then it becomes

$p(t)=2\times 80=160$

so, time taken to reach this above mentioned population is given by

$160=0.3t^2+6t+80\\\\160-80=0.3t^2+6t\\\\80=0.3t^2+6t\\\\0.3t^2+6t-80=0\\\\\text{using quadratic formula ,we get }\\\\t_{1,\: 2}=\frac{-60\pm \sqrt{60^2-4\cdot \: 3\cdot \: 800}}{2\cdot \: 3}\\\\t=-29.14\ and\ t=9.149$

now, we know that time can't be negative so, we take t=9.149 years.

hence, at 24 february, 2014 the population gets twice of its initial population.

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Mathematically, explain how a car (A) with mass of 500 kg and velocity of 2 m/s has the same kinetic...

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