If 100 grams of water is to be heated from 24.0°C to 100.0°C to make a cup of tea, how much heat must be absorbed? The specific heat of water is 4.184 J/g∙°C Solve the problem and show your work.

76*

Explanation:

Q= 31,798.4

Explanation:

You would use the specific heat formula which is Q=mCΔt

m(mass)=100

C(Specific heat capacity)= 4.184

Δt(change in temperature)=24-100=-76 or just 76 in this case

so Q=(100)(4.184)(76)=

418.4(76)=31,798.4

Therefore the missing value Q(heat lost or gained) equal 31,798.4

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