A small business operates3 pieces of equipment for 9 hrs continuously per day for 6 days a week if the 3 equipment consume 10kw, 2.5kw and 600watts respectively calculate the weekly cost if charge per unit is 7.9 pence​

5588.46 pence

Explanation:

The following data were obtained from the question:

Power of 1st equipment (P₁) = 10 KW

Power of 2nd equipment (P₂) = 2.5 KW Power of 3rd equipment (P₃) = 600 W

Time (t) = 9 hours per day.

Cost per day = 7.9 pence​ per unit KWh

Cost for a week =?

Next, we shall convert 600 W to KW. This can be obtained as follow:

1000 W = 1 KW

Therefore,

600 W = 600 W × 1 KW / 1000 W

600 W = 0.6 KW

Next, we shall determine the total power consumed. This can be obtained as follow:

Power of 1st equipment (P₁) = 10 KW

Power of 2nd equipment (P₂) = 2.5 KW Power of 3rd equipment (P₃) = 0.6 KW

Total power (Pₜ) =?

Pₜ = P₁ + P₂ + P₃

Pₜ = 10 + 2.5 + 0.6

Pₜ = 13.1 KW

Next, we shall determine the total time of operation in a week. This can be obtained as follow:

From the question given above, we were told that:

1 day = 9 hours

Therefore,

6 days = 6 × 9 = 54 hours.

Thus, the total time of operation is 36 hours.

Finally, we shall determine the cost operating the three (3) equipment for a week (i.e 6 days). This can be obtained as follow:

Total power (Pₜ) = 13.1 KW

Total time (tₜ) = 54 hours

Cost per day (Cₔ) = 7.9 pence​ per unit KWh

Cost per week (Cᵥᵥ) =?

Cᵥᵥ = Pₜ × tₜ × Cₔ

Cᵥᵥ = 13.1 × 54 × 7.9

Cᵥᵥ = 5588.46 pence

Therefore, the cost operating the three (3) equipment for a week (i.e 6 days) is 5588.46 pence