A stone with a mass of 0.600 kg is attached to one end of a string 0.900 m long. The string will break if its tension exceeds 50.0 N. The stone is whirled in a horizontal circle on a frictionless tabletop; the other end of the string remains fixed. A. Draw a free-body diagram of the stone.
B. Find the maximum speed the stone can attain without breaking the string.

8.7 m/s

Explanation:

Given data

Mass= 0.6kg

radius= 0.9m

Force= 50N

A. Please see attached the FBD of the stone

B. Apply the formula

F= mv^2/r

Substitute

50= 0.6*v^2/0.9

cross multiply

50*0.9= 0.6v^2

45= 0.6v^2

v^2= 45/0.6

v^2= 75

v= √75

v= 8.7 m/s

Hence the maximum speed attained without breaking the string is 8.7 m/s

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