A stone is thrown horizontally at 30m/s from a tall cliff. i. Calculate its horizontal position and vertical position at 2 seconds interval for the first 10 seconds.
ii. Plot a graph using positions in (i) showing trajectory of the stone

x(2) = 30(2) = 60 m

y(2) = ½(-9.8)2² = -19.6 m

x(4) = 30(4) = 120 m

y(4) = ½(-9.8)4² = -78.4 m

x(6) = 30(6) = 180 m

y(6) = ½(-9.8)6² = -176.4 m

x(8) = 30(8) = 240 m

y(8) = ½(-9.8)8² = -313.6 m

x(10) = 30(10) = 300 m

y(10) = ½(-9.8)10² = -490 m

v 154.9= 0.9 length length s little over 154.9cm

an energy transformation flow diagram is shown

where is it ?