![m_{i} \cdot [c_{i}\cdot (T_{1}-T_{2}) - L_{f} + c_{w}\cdot (T_{2}-T_{3})] + m_{w} \cdot c_{w}\cdot (T_{4}-T_{3}) = 0](/tpl/images/1348/5993/4cb16.png)
(1)
- Mass of ice, in grams.
- Mass of the juice, in grams. 
- Specific heat of ice, in joules per gram-degree Celsius.
- Specific heat of water, in joules per gram-degree Celsius.
- Latent heat of fusion, in joules per gram. 
- Initial temperature of ice, in degrees Celsius.
- Melting point of water, in degrees Celsius. 
- Final temperature of the ice-juice system, in degrees Celsius. 
- Initial temperature of the juice, in degrees Celsius. 
, 
, 
, 
, 
, 
, 
and 
, then the mass of the juice is:![m_{w} = \frac{m_{i}\cdot [c_{i}\cdot (T_{1}-T_{2}) - L_{f} + c_{w}\cdot (T_{2}-T_{3})]}{c_{w} \cdot (T_{3}-T_{4})}](/tpl/images/1348/5993/375ff.png)
![m_{w} = \frac{(100\,g)\cdot \left[\left(2.090\,\frac{J}{g\cdot ^{\circ}C} \right)\cdot (-10\,^{\circ}C) - 334\,\frac{J}{g} +\left(4.18\,\frac{J}{g\cdot ^{\circ}C} \right)\cdot (-10\,^{\circ}C) \right]}{\left(4.180\,\frac{J}{g\cdot ^{\circ}C} \right)\cdot (-10\,^{\circ}C)}](/tpl/images/1348/5993/15d34.png)
100 g of Ice at -10°C is added into a
liquid juice at 20°c . The temperature of Juice
dropped...
Physics, 26.05.2021 09:40 melanysanson11
100 g of Ice at -10°C is added into a
liquid juice at 20°c . The temperature of Juice
dropped to l0°c after all the Ice has melted.
Calculate the mass of the Juice responsible
for metting an Ice
Answers: 2
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