What is acceleration for the first 10 seconds? Use that a to find the speed of the particle when t = 10 seconds, v(t=10)? b) What is the position of the of the particle when t = 10 sec,
x(t=10)?
c) From 10 to 15 seconds, what is a? So what is v?
d) How far does the particle move between 10-15 seconds?
e) From 15 to 20 seconds, how far does the particle move?
f) What is the speed when t = 20 sec?

answer: 802.3 kilo joules of energy represents 191.75 kilo calorie of energy.

explanation:

energy released during combustion of one mole methane = 802.3 kilo joules

if 1 kilo joule = 0.239006   kilo calorie

then ,802.3 kilo joule will be = 802.30.239006 kilo calorie

802.3 kilo joule = 191.75 kilo calorie

hence, the energy in kilo calorie is 191.75 kilo calorie.

we have been given a quadratic function and we need to restrict the domain such that it becomes a one to one function.

we know that vertex of this quadratic function occurs at (5,2).

further, we know that range of this function is .

if we restrict the domain of this function to either or , it will become one to one function.

let us know find its inverse.

upon interchanging x and y, we get:

let us now solve this function for y.

hence, the inverse function would be if we restrict the domain of original function to and the inverse function would be if we restrict the domain to .

snell's law

refractve index = sin incidence / sin refraction