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Physics, 22.07.2021 07:50 sanfordl

: Ném một vật lên cao với vận tốc ban đầu v0 = 15(m/s) theo phương hợp với phương ngang một góc =30. Bỏ qua sức cản khơng khí lấy g = 9,8(m/s2). Bán kính cong của quỹ đạo tại vị trí cao nhất của vật là:

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: Ném một vật lên cao với vận tốc ban đầu v0 = 15(m/s) theo phương hợp với phương ngang một góc =30...
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