Suppose that you put one air molecule on your desk, so it is in thermal equilibrium with the desk at 16.9°C. Suppose that there is no atmosphere to get in the way of this one molecule bouncing up and down on the desk. Calculate the typical height that the air molecule will be above your desk, so that Mgy ≈ kBT. (For simplicity, assume that the air molecule is diatomic nitrogen.) kB = 1.3807e-23

Two students, each riding bicycles, start from the same apartment building and ride to the same building on campus, but each takes a different route. the first student rides 1100 m due east and then turns due north and travels another 1430 m before arriving at the destination. the second student heads due north for 1930 m and then turns and heads directly toward the destination.at the turning point, how far is the second student from the destination?