A .5 kg squirrel jumps off a branch thta is 2.00 meters above level ground with a velocity of 10.0 m/s at a 30 degree angle then pauses to dig for a nut. After 15 seconds of digging the squirrel runs gingerly away at 5 m/s. what is the squirrel's position vector with respect to the squirrels starting location after 1 second and after 5 seconds

Wavelength divides in half and speed stays the same.

Answerthe energy required is 1.60 × 10⁻¹⁸ j, to three significant figures.explanationwe define electric potential as the ratio electric potential energy to the charge,    then the following gives us the potential difference,      the formula  may be on your formula sheet.the change in electric potential energy would be the energy that would needed to move it from point a to point b. solving for that, we get    using q = 8.00  × 10⁻¹⁹ c and  δv = 2.00 v, we get    the energy required is 1.60 × 10⁻¹⁸ j, to three significant figures.