A 570 kg elevator accelerates downwards at 1.5 m/s2 for the first 13 m of its motion. Part A
How much work is done during this part of its motion by the cable that lowering the elevator? Neglect any friction or air resistance.

Answer:

11115 J

Hope you could get an idea from here.

Doubt clarification - use comment section.

all of the answers are correct.

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explanation:

continuous conducting path for current, power supply