A boy starts moving from origin in - ve x direction with acceleration 2 m/s^2 for 5 second. Then he suddenly reserves his direction without changing his speed and moves with that constant speed for further 5 seconds. find
a) final position of boy
b) displacement in 10s
c) distance covered

Is there a picture to go along with this

Ithink it’s 98 because jajajjajansmsmjs

Since you have not included the experiment situation and the data, of course, i can not give you specific details about it. but i can you with this question.1) i will assume that the motion is projectile (parabolic) motion.2) yes, the horizontal distance depends on the horizontal velocity as, naming vx the horizontal velocity and t the time, it is: x = vx × t3) now, observe that the flight time depends on the vertical velocity as, naming voy the initial vertical velocity, t the time and y the vertical distance before reaching the ground: y = yo + voy×t - gt² / 2.the higher the initial vertical velocity (voy) the longer the object will be flying and so t will be higher in the equation for the horizontal distance.that explains the relationship between the horizontal distance and the horizontal velocity.