What is the electrical force between q1 and q2? Recall that k = 8. 99 × 109 N•meters squared over Coulombs squared. 4. 3 × 1010 N 3. 5 × 1010 N –5. 4 × 1010 N –5. 8 × 1010 N.

electrical potential energy =0.072 j

explanation:

electrical potential energy is given by

u= q δv

q= charge=6 c

δv= potential difference and is given by

δv= e d

e= electric field

d= distance=5 mm=0.005 m

δv=2.4 (0.005)=0.012 v

now electric potential energy= u= q δv

u=6 (0.012)

u=0.072 j

i do.

explanation:

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