Water flows in a flexible tube of radius 1.5 cm at the floor level of a house. The tube is joined a second tube of smaller radius (1.2 cm), which runs to a floor 7.2 m above. If the pressure in the lower tube is 214 kPa, and the pressure in the upper tube is 107 kPa, what is the speed of water in the upper (smaller radius) tube?

Try c ? that’s what i got

2.77 x 10^-3 its for plato user 

Distance covered, s = 8ft - 4ft = 4 ftinitial velocity, u = 34 ft/sthe acrobat is moving upwards and therefore, a = -g = -9.81 m/s^2 = 32.19 ft/s^2applying equation of motion; s = ut -1/2gt^2then,4 = 34t -1/2*32.19t^24 = 34t - 16.095t^2rearranging; -16.095t^2 + 34t - 4 = 0solving the quadratic equation; t = {-34 +/- sqrt [34^2 - 4(-16.)]}/2(-16.095) = 1.06 +/- 0.93 = 0.13 or 1.99the acrobat will take 0.13 seconds to be at 8 ft above the ground. additionally, once at the maximum height, the acrobat will move down and be at the same spot (that is height) after 1.99 seconds moving down.