A 2.5 Kg watermelon is dropped off an 8-meter balcony. What will the watermelon’s velocity be right before it hits the ground?

The watermelon’s velocity right before it hits the ground is 12.52 m/s.

The principle of conservation of mechanical energy states that the total energy of an isolated system is always conserved.

P.E = K.E

mgh = ¹/₂mv²

gh = ¹/₂v²

v = √2gh

where;

The watermelon’s velocity right before it hits the ground is calculated as follows;

v = √(2 x 9.8 x 8)

v = 12.52 m/s

Learn more about conservation of mechanical energy here:

dec 23, 2016 - a load of bricks weighing 680 n a distance of 10 m across a parking lot. if if the worker pushes the cart with a constant force of 209 n, what work= force x distance = 220 n x 10 m = 2200 n.m = 2200 j i don't know where the person got it from, but the initial part, work= force x distance me.