If an object 18 millimeters high is placed 12 millimeters from a diverging lens and the image is formed 4 millimeters in front of the lens, what is the height of the image? a. 14 millimeters b. 6 millimeters c. 22 millimeters d. 8 millimeters

As per the question the height of object  18 mm

The object distance [u] is given as 12 mm

The image distance[v] is given as 4 mm

The lens taken here is a diverging nature.hence the lens is a concave lens.

The image formed in a concave lens is always virtual,erect and diminished.

As per the question the image is formed in front of the lens.

we have to calculate the image height  which is calculated as follows-

putting the sign convention on the above data we get

u= -12 mm              v=-- -4 mm     [ - sign is due to the fact that the measurement is opposite to the direction of light

               [the height is positive as it is above the principal axis]

As per the magnification formula we know that

Magnification

                        ⇒

                        ⇒

                        ⇒

                                      = 6 mm [ans]

Hence B is right.

gans

explanation:

vestigial organs (like your appendix) are organs that no longer serve a purpose.

as we probably am aware that our atmosphere or air have various levels, each level has different gasses, and each gas has another porousness. at the point when the light originates from lower porousness to higher penetrability, it alters its course. with the goal that implies that when the light originates from the moon to the earth, it alters it's course a lot more occasions. it essentially implies that the state of the light piece of the moon is changed on the earth.

not copied too! hope this !

joke:

h o h o hope you have a merry christmas!