Ashopper in a supermarket pushes a loaded cart with a horizontal force of 13 n. the cart has a mass of 34 kg. the acceleration of gravity is 9.8 m/s 2 . disregarding friction, how far will the cart move in 3.2 s, starting from rest? answer in units of m

2.0 m Since we've been told to ignore friction, then we can also ignore gravity since all it's doing is contributing to the normal force which is only of interest if we're paying attention to friction. So how fast will 13 N of force accelerate 34 kg of mass? Since a newton is kg*m/s^2 and we want to get m/s^2, a simple division should be able to cancel out the kg. So: 13 kg*m/s^2 / 34 kg = 0.382352941 m/s^2 The distance an object moves under constant acceleration is d = 0.5 AT^2 So let's substitute the known values and calculate the distance. d = 0.5 AT^2 d = 0.5 0.382352941 m/s^2 * (3.2 s)^2 d = 0.191176471 m/s^2 * 10.24 s^2 d = 1.957647059 m Rounding to 2 significant figures gives 2.0 meters

The answer is 12, for the points