If an object moved at 30.0 m/s and at a later time covers half the distance in the same time, calculate its new speed.

15 m/s

Explanation:

Let in time t the object moves a distance d with speed 30 m/s.

Again in time t, it covers half of distance and the new speed is v.

So, d = 30 x t (1)

d/2 = v x t

Put d = 30 t from equation (1)

30 x t / 2 = v x t

v = 15 m/s

e

explanation:

there is no change in the electric potential energy as it is in rest on both conditions.

neither accurate nor precise.