Advanced Placement (AP), 23.10.2019 00:10 dontcareanyonemo

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Answer from: liaholmes8

Problem One

The volume of a cone is

V= 1/3 * pi * r^2 * h

h = 20 so

V = 1/3 * pi * r^2 * 20 Multiply by 3

3V = pi * r^2 * 20 Divide by 20*pi

3V/(20*pi) = r^2 Take the square root of both sides.

√(3V/(20*pi) ) = √r^2 Switch

√r^2 = √(3V/(20*pi) )

r = √(3V/(20*pi) )

A is wrong because it is taking the cube root to find r. Only the square root is needed.

C is wrong because the right side is a square root, not squared.

D is wrong because it is the reciprocal (up side down) of the answer.

The answer is B.

Problem Two

Before you do anything else, find out what she charges for 1 dog.

27 dogs = 324

1 dog = x Cross multiply

27x = 324 Divide by 27

x = 324 / 27 Do the division

x = 12 dollars for 1 dog.

Now you can look at the graph. Plot the following points (x < 16)

Number dogs Amount

1 12

3 36

5 60

That's enough to get the line which I've given you below.

Answer from: aaronpmoore1010

1st Question :

We know that Volume of Cone is given by : $\frac{\pi r^2h}{3}$

Given the height of the Cone : 20 inches

$\implies v = \frac{20\pi r^2}{3}\\\\\implies 3v = 20\pi r^2\\\\\implies r(v) = \sqrt{\frac{3v}{20\pi}}$

2nd Question :

Given that : the amount of money jeannine earns varies directly with the number of dogs she bathes.

⇒ y ∝ x

let us find the money jeannine gets for one dog wash.

⇒ $\frac{y_1}{y_2} = \frac{x_1}{x_2}$

⇒ y₁ = 324 and x₁ = 27 and x₂ = 1

$\implies \frac{324}{y} = \frac{27}{1}\\\\\implies Amount\;for\;one\;dog = \frac{324}{27} = 12$

So , The Equation is : y = 12x

Answer from: Quest

Dis an orderly way to conduct research

Answer from: Quest

Like many students at university, you may be unhappy about the results you attain in exams. you may feel that even with all you are doing there must be something more -- or different-- you could be doing to get better grades. we have all at some time or other heard of that student who only studies a couple of hours for final exams and scores a's every time. we stand in awe of those who seem to breeze through without undue effort and seem to need very little in the way of studying to nail an exam. the reasons for success, in what i think are the vast majority of cases, are less esoteric than many students think: successful students consistently apply a series of productive strategies with view to attaining clearly identified learning and grade goals throughout the academic term.

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