Advanced Placement (AP), 01.12.2019 06:31 Tnaaasty8812

support or refute the assertion that
john brown was a martyr.

Answers: 1

Show answers

Answers

Based on the death and general historical role of John Brown, it is most reasonable to argue in support of the statement that John Brown was a martyr.

Explanation:

As one of the first white abolitionists (people who advocated for the abolition of slavery in the USA), John Brown was famous for promoting armed insurrection against slavery, while pacifism was more common among other members of the abolitionists movement.

In 1859 he have organised and armed raid on Harpers Ferry. After a two day attack, John Brown and 18 other insurgents were arrested on October 18, 1859. Brown has not received as much of armed support from slaves as he expected and was defeated so quickly because so only initial 18 insurgents were fighting by his side.

Meanwhile, his subsequent 42-day imprisonment, execution and consistent ideology gained John Brown strong martyr position in the American history. He ultimately became a textbook character. For example, the marching song ‘John Brown’s Body’ became the basis for ‘The Battle Hymn of the Republic’ (1861).

Answer from: Quest

If we perceive our body as too fat even though our body is not we might diet until we think we aren't fat and if we perceive our body as too thin we might binge eat until we think we are average weight ( not too thin and not too fat )

Answer from: Quest

The answer is (d) 7/2======we have $f(x) = \begin{cases} x & \text{ for } x \le 0 \\ x + 1 & \text{ for } x \ \textgreater \ 0 \end{cases}$ we also have an integral $\displaystyle\int_{-2}^1 x\, f(x)\; dx$ notice how function f splits up at x = 0. there's a left piece and a right pieceso we'll need to do the same thing with our integral: split it at x = 0we use a property of integrals that allows us to split up and sum: $\displaystyle\int_{-2}^1 x\, f(x)\; dx = \displaystyle\int_{-2}^0 x\, f(x)\; dx + \displaystyle\int_{0}^1 x\, f(x)\; dx$ notice that for the piecewise function f, the function has the equationf(x) = x when x ≤ 0. so for the integral $\int_{-2}^0 x\, f(x)\; dx$ , f(x) = x so it changes into $\begin{aligned} \int_{-2}^0 x\, f(x)\; dx & = \int_{-2}^0 x \cdot x\; dx \\ & = \int_{-2}^0 x^2\; dx \\ & = \left[\frac{x^3}{3}\right]_{-2}^0 & & \text{\footnotesize antidifferentiate} \\ & = 0 - \frac{(-2)^3}{3} \\ & = \frac{8}{3} \end{aligned}$ for the piecewise function f, the function has the equationf(x) = x+1 when x > 0. for the integral $\int_{0}^1 x\, f(x)\; dx$ , we have $\begin{aligned} \int_{0}^1 x\, f(x)\; dx & = \int_{0}^1 x(x+1)\; dx \\ & = \int_{0}^1 (x^2+x)\; dx \\ & = \left[ \frac{x^3}{3} + \frac{x^2}{2}\right]_0^1 \\ & = \frac{1}{3} + \frac{1}{2} - 0 = \frac{5}{6} \end{aligned}$ therefore, back to our splitted integral: $\begin{aligned} \displaystyle\int_{-2}^1 x\, f(x)\; dx & = \displaystyle\int_{-2}^0 x\, f(x)\; dx + \displaystyle\int_{0}^1 x\, f(x)\; dx \\ & = \frac{8}{3} + \frac{5}{6} \\ & = \frac{7}{2} \end{aligned}$
Can anyone me on this ap calc question? ?

Can anyone me on this ap calc question? ?

Another question on Advanced Placement (AP)

Advanced Placement (AP), 23.06.2019 13:10

You want free brainliest + free points? answer this drivers ed question and you shall receive : )) gas, food, and lodging are in rural areas. a. easily accessible b. always separated c. found everywhere d. less accessible

Answers: 2

Answer

Advanced Placement (AP), 24.06.2019 02:00

If the limit, as x approaches infinity (or negative infinity) of a function is equal to a, we say that the line y = a is a of the function f.

Answers: 2

Answer

Advanced Placement (AP), 25.06.2019 19:30

Elias needs to practice the piano, but instead he sends over 100 texts to his friends. this is an example of wasting talent getting distracted allowing other to set goals

Answers: 1

Answer

Advanced Placement (AP), 26.06.2019 18:00

What property does soil or rock need to be permeable? a.)young b.)old c.)non porous d.)porosity

Answers: 1

Answer

You know the right answer?

support or refute the assertion that
john brown was a martyr....

Questions