Advanced Placement (AP), 10.03.2020 16:41 ybetancourt1

Land conservation is a worldwide priority. There are several methods to prevent the loss of land due to a variety of reasons. Which method is not a way to conserve land?

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Answer from: sabahfayaskhan

Cut and burn methods of clearing land.

Explanation:

The land conservation should be as one of the primary things that need to be done worldwide. The reason for this is simple, we grow or harvest our food from it. Unfortunately, the human activities and irresponsibility has led to dramatic decrease in fertile soil around the globe, as it has increased the erosion significantly, and it has also managed to destroy the soil on the long term in many cases.

The cut and burn method is one of the most problematic. It is a method through which the people cut and then burn all of the vegetation in a particular area in order to open up the space for agriculture. While this works on the short term, it doesn't on the long term, because the soil is often of relatively low quality, and without its natural protection it erodes rapidly. As the soil becomes infertile, the people just continue with the process, leaving empty and destroyed land behind them.

Answer from: Quest

after lydia compare her check register to her bank statement, and the ending balances do not seem to match. then, she must make a bank reconciliation by putting the data all together.

to do this, she need to determine the bank ending balance. after, add the deposits in transit then deduct the outstanding checks. moreover, if the actual checkbook balance does not equal this number, check again for transporting errors by subtracting the balances and add the difference to nine. sometimes, a mathematical error can happen but a bank reconciliation is a great tool to resolve the discrepancies.

Answer from: Quest

The answer is (d) 7/2======we have $f(x) = \begin{cases} x & \text{ for } x \le 0 \\ x + 1 & \text{ for } x \ \textgreater \ 0 \end{cases}$ we also have an integral $\displaystyle\int_{-2}^1 x\, f(x)\; dx$ notice how function f splits up at x = 0. there's a left piece and a right pieceso we'll need to do the same thing with our integral: split it at x = 0we use a property of integrals that allows us to split up and sum: $\displaystyle\int_{-2}^1 x\, f(x)\; dx = \displaystyle\int_{-2}^0 x\, f(x)\; dx + \displaystyle\int_{0}^1 x\, f(x)\; dx$ notice that for the piecewise function f, the function has the equationf(x) = x when x ≤ 0. so for the integral $\int_{-2}^0 x\, f(x)\; dx$ , f(x) = x so it changes into $\begin{aligned} \int_{-2}^0 x\, f(x)\; dx & = \int_{-2}^0 x \cdot x\; dx \\ & = \int_{-2}^0 x^2\; dx \\ & = \left[\frac{x^3}{3}\right]_{-2}^0 & & \text{\footnotesize antidifferentiate} \\ & = 0 - \frac{(-2)^3}{3} \\ & = \frac{8}{3} \end{aligned}$ for the piecewise function f, the function has the equationf(x) = x+1 when x > 0. for the integral $\int_{0}^1 x\, f(x)\; dx$ , we have $\begin{aligned} \int_{0}^1 x\, f(x)\; dx & = \int_{0}^1 x(x+1)\; dx \\ & = \int_{0}^1 (x^2+x)\; dx \\ & = \left[ \frac{x^3}{3} + \frac{x^2}{2}\right]_0^1 \\ & = \frac{1}{3} + \frac{1}{2} - 0 = \frac{5}{6} \end{aligned}$ therefore, back to our splitted integral: $\begin{aligned} \displaystyle\int_{-2}^1 x\, f(x)\; dx & = \displaystyle\int_{-2}^0 x\, f(x)\; dx + \displaystyle\int_{0}^1 x\, f(x)\; dx \\ & = \frac{8}{3} + \frac{5}{6} \\ & = \frac{7}{2} \end{aligned}$
Can anyone me on this ap calc question? ?

Can anyone me on this ap calc question? ?

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