Using tthe following table of a school bus during morning pickups to calculate its average speed between 0 h and 2.34 h. plase help
sorry wrong subject it's science

6.983 km/hr

Explanation:

This problem asks for the the average rate of change, which is Δy/Δx. In this case, the time represents x, and the position represents y. The average rate of change is (16.34 - 0.0)/(2.34 - 0.000) ≈ 6.983 km/hr

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answer: all of the above

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