If there were no air resistance, with what speed would drops hit the Earth if they fell from a cloud 3063 m above the Earth’s surface? The acceleration of gravity is 10 m/s 2

Explanation:

One

d = 3063 m

a = 10 m/s^2

vi = 0

vf = ?

vf^2 = vi^2 + 2*a*d

vf^2 = 2*10*3063

√vf^2 = √61260

vf = 247.51 m/s

Two

vi = 0

vf = ?

a = 10 m/s^2

t = 18 s

a = (vf - vi) / t

10 = (vf - 0) / 18

10 * 18 = vf

180 m/s = vf

answer: all of the above

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