Advanced Placement (AP), 17.10.2020 03:01 kaciejackson91

Prompt Answer questions 1-12 in "Questions on Rhetoric and Style" on p. 778 of The Language of Composition. (2nd edition:
Answer questions 1-12 on p. 411.)
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He wanted his reader to view him as someone with a “crazy” persona. He wanted to be viewed as someone who was outrageous and overacted with beliefs that were out of line. This is essential so as to invoke some emotions from them.I noticed when he first started describing the reasoning for his proposal. I think a modern audience would catch on quicker because today we have a better idea of satire and read about it as well as work with it a lot of the time so we know when we see it as opposed to when it was a newer thing.His diction of pointing out the wrongdoings of the people. He talks about the people in a harsh manner and describes them as problems not people. He chooses these words as it sets a mood that this piece is to change the ways of humanity.Because of the ridiculous nature of the proposal, he wanted the readers to first see the purpose of this kind of proposal. If readers saw the proposal before they saw the reasoning they may think it is too crazy and would not continue reading and therefore would not see that it is satire.The purpose of this kind of strategy is to further invoke the imagination of the readers as to the message Swift wants to convey.Swift's use of statistics to back up his appeal for these values and the overall effect of his proposal is a rhetorical strategy that elicited the consciousness of the audience. This further supports his argument as it adds logic to the proposal and makes people think it is a smart idea and they keep reading.The purpose of this additional proposal is to create an atmosphere of more anger and ridiculousness to further push the readers to action. Swift targets people who make the most of their ill-gotten opportunities to take advantage of people who they got to believe and surrender to them.His assumptions addressed his concerns of people taking up most of the power and the poor people becoming poorer and poorer. He assumes that people will read these and will be willing to make those changes and that it is a simple task despite it not being so and it is actually quite a challenge.He discusses some solutions so as to help lessen the damage that his proposal would do. The purpose of this is to let the readers imagine how difficult the country has been that it came to the point that this kind of proposal is the only solution.He noted at the end that this proposal came from the very ill-fated thoughts of a visionary which makes this proposal all the more satiric. His tone is serious.The final paragraph further puts a final closing/clamp on the satiric nature of the proposal.

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Answer: the interval on which the curve is concave up is (-∞, -1/2)====== $\displaystyle y = \int_{0}^x \frac{1}{1 + t + t^2} \; dt$ we find the interval where this curve is concave up by finding the interval in which the 2nd derivative is positive.differentiate the curve equation with respect to x $\begin{aligned} \frac{dy}{dx} & = \frac{d}{dx} \int_{0}^x \frac{1}{1 + t + t^2} \; dt \end{aligned}$ let the function f denote be the anti-derivative of the inside expression, i.e. a function such that $(d/dx)f(x) = 1/(1 + t + t^2)$ .then use the fundamental theorem of calculus: $\begin{aligned} \frac{dy}{dx} & = \frac{d}{dx} \int_{0}^x \frac{1}{1 + t + t^2} \; dt \\& = \frac{d}{dx} \big[ f(x) - f(0) \big] & & \text{\footnotesize apply ftc} \\ & = \frac{d}{dx}f(x) - 0 \\ & = \frac{1}{x + x + x^2} & & \text{\footnotesize since $\frac{d}{dx}f(x) = \frac{1}{1 + x + x^2}$ } \end{aligned}$ differentiate again to get second derivative. we can use chain rule with 1/x as the outside function and 1 + x + x² as the inside function $\begin{aligned} \frac{d}{dx} \left( \frac{dy}{dx} \right) & = \frac{d}{dx}\left(\frac{1}{1 + x + x^2} \right) \\ \frac{d^2y}{dx^2} & = \frac{-1}{\left(1 + x + x^2\right)^2} \cdot \tfrac{d}{dx}(1 + x + x^2) \\ & = \frac{-1}{\left(1 + x + x^2\right)^2} \cdot (1 + 2x) \\ & = \frac{-(1 + 2x)}{\left(1 + x + x^2\right)^2} \end{aligned}$ find critical numbers of the second derivative. these numbers are where the 2nd deriv. is undefined or zero.where the 2nd derivative is zero: set (d²y/dx²) to equal 0 and solve for x $\begin{aligned} 0 & = \frac{-(1 + 2x)}{\left(1 + x + x^2\right)^2} \\ 0 & = -(1+2x) \\ -1 & = 2x \\ x & = -1/2 \end{aligned}$ where the 2nd derivative is undefined: if the denominator is equal to zero, the derivative will be undefeined. attempting to solve the equation 1 + x + x² = 0results in a discriminant of $b^2 - 4ac = 1^2 - 4(1)(1) = -3$ meaning that the equal 1 + x + x² = 0 has no real solutions and therefore will never equal zero.======our only critical number is x = -1/2.this forms two intervals to test the sign for: (-∞, -1/2) and (-1/2, ∞)test values into the 2nd derivative for (-∞, -1/2)if we try x = -1, we get $\begin{aligned} \left.\frac{d^2y}{dx^2}\right|_{x = -1} & = \frac{-(1+2(-1))}{\left(1+(-1)+(-1)^2\right)^2} \\ & = \frac{-(1-2)}{1} \\ & = 1 \end{aligned}$ so the since the 2nd derivative of the curve is positive on the interval (-∞, -1/2), the curve is concave up on (-∞, -1/2)test values into the 2nd derivative for (-1/2, ∞)if we try x = 0, we get $\begin{aligned} \left.\frac{d^2y}{dx^2}\right|_{x = 0} & = \frac{-(1+2(0))}{\left(1+(0)+(0)^2\right)^2} \\ & = \frac{-(1)}{1} \\ & = -1 \end{aligned}$ so the since the 2nd derivative of the curve is positive on the interval (-∞, -1/2), the curve is concave down on (-∞, -1/2).the interval on which the curve is concave up is (-∞, -1/2)

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Prompt Answer questions 1-12 in "Questions on Rhetoric and Style" on p. 778 of The Language of Comp...

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