A car is traveling down a long, steep hill. The elevation, E, above sea level (in feet) of the car when it is d miles from the top of the hill is given by E = 7500– 250d, where d can be any number from 0 to 6. A. Find the slope and intercepts of the graph of this function and explain what they mean in the context of the moving car.

B. Another car is traveling up the same long steep hill. This car is at an elevation of 250 and is traveling at 250 miles. How many miles will it take for both cars to reach each other?

C. What is the elevation of that meeting point? Show your work. *Please Show Work

*Please Show Work*

Answercommunity of population;

Answer(1) year suspended

Ithink it’s a but it might be wrong so sorry

You need to figure out at which x-value does the graph has a tangent line slope of -1.remember, the derivative is the slope of the tangent line. so find the derivative function and set it to equal -1 to find the x-value that will have a tangent line slope of 0.differentiate with the chain rule.    set the derivative to equal -1 and solve for x.      take log base 10 of both sides. also recall that  .    so the x-coord of the point of tangency is .the y-coordinate of this point of tangency can be calculated using the original function:     using point-slope form, the equation of the tangent line is      the x-intercept of this tangent line is when the graph is at y=0.    this rounds off to  .choice c.