Advanced Placement (AP), 09.02.2021 21:20 donavancoulter712

At 65 C, the value of Kw is 1.0 x 10-13? What is the [H+ ] in water at this temperature?

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Answer from: Quest

light-year

the distance that light travels in a vacuum in one year, equal to about 9.46 trillion km (5.88 trillion mi). light-years are used in measuring interstellar and intergalactic distances.

parsec

a unit of distance used in astronomy, equal to about 3.25 light years (3.08 × 1016 meters).

parallax

the apparent angular displacement of a celestial body due to its being observed from the surface instead of from the center of the earth (diurnal parallax or geocentric parallax) or due to its being observed from the earth instead of from the sun (annual parallax or heliocentric parallax)

absolute magnitude

the magnitude (brightness) of a celestial object as it would be seen at a standard distance of 10 parsecs.

apparent magnitude

the magnitude of a celestial object as it is actually measured from the earth.

redshift

an increase in the wavelength of radiation emitted by a celestial body as a consequence of the doppler effect.

the great thing about your imagination is that it doesn't have to make sense! if i were you i would be stuck in space, no communication with earth travelling around and around, you can only guess how long its been since your communication broke down. you land on an undiscovered planet, you do a scientific investigation examining the elements and conditions. you come across alien lifeforms.

best of luck!

Answer from: Quest

See diagram.we use washers to get the area and we will be integrating with respect to xouter radius is the distance between y = e^x and y = -1 $r_{\text{out} } = e^x ) = e^x + 1$ inner radius of washer is the distance between y = 1 and y = -1 $r_{\text{in} } = 1 - (-1) = 2$ the area of one cross-section of a washer is $\begin{aligned} a(x) & = \pi(r_{\text{out} } )^2 - \pi(r_{\text{in} } )^2 \\ & = \pi(e^x + 1 )^2 - \pi(2)^2 \\ & = \pi \big[(e^x + 1 )^2 - 4 \big] \end{aligned}$ solid lies between x = 0 and x = 2. the volume is $\begin{aligned} v & = \int_0^2 a(x) dx \\ & = \int_0^2 \pi \big[(e^x + 1 )^2 - 4 \big] dx \end{aligned}$ if you need this expanded, then $\begin{aligned} v & = \int_0^2 \pi \left(e^{2x} + 2e^x + 1 - 4 \right) dx \\ & = \int_0^2 \pi \left(e^{2x} + 2e^x -3 \right) dx \end{aligned}$ the question doesn't say to evaluate, so we're done.

Answer from: Quest

Option b is correct. the violation of society's formally enacted criminal law

Answer from: Quest

There really doesn't seem to be anything remotely advanced about this question, especially for high school.that being said, the actual correct answer may depend on the lesson you received.but i'll use common knowledge to you out here. an atlas is a map, a flat map which depicts the world, all the continents and large bodies of water and etc. an almanac is basically a yearly calendar. this depicts all the stuff that happened during the year it was released after, such as important events, sporting stuff, astronomical data, etc. it really depends on what type of almanac you go for.encyclopedias contain vast knowledge about just about everything important around the globe. each encyclopedia is generally focused on a topic and it's relating topics, ordered by each book alphabetically. information resource can be anything. internet, newspaper, talking dog of pure wisdom (joking), the bible (or the religious book for whatever religion is in question), etc. all of these are considered information resources, as they all provide information on their respective topics (the internet is pretty much all topics)now, once again, your true answer will be based on whatever it is you learned, which i would not know. my answer will simply be using common knowledge.but your answers that line up with weather, sports, and business would be an almanac, information resources, and encyclopedia. unfortunately, in today's world, they have books for everything. they have almanacs for weather, sports, and business, and they also have encyclopedia's for those as well. and of course, you can find all of that using information resources as well. the only truly incorrect answer here is atlases. ~hope this !

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