Advanced Placement (AP), 16.11.2021 14:00 AriaMartinez

A study found that men report high self-efficacy for both traditionally male jobs and traditionally female jobs. Women, on the other hand, report high self-efficacy for traditionally female jobs, but low self-efficacy for traditionally male jobs. Why do you think it is that we see these gender differences in regard to confidence in job aptitude?

Answers: 1

Show answers

Answers

Answer from: Quest

orienteering is for all ages and degrees of fitness and skill.

Answer from: Quest

Answer(1)=c; expanded food and nutrition education program; answer(2)=a; elderly and those with health issues; answer(3)=nutrition program for the elderly;

Answer from: Quest

True because the skills you do at work and home are different

Answer from: Quest

Answer: the interval on which the curve is concave up is (-∞, -1/2)====== $\displaystyle y = \int_{0}^x \frac{1}{1 + t + t^2} \; dt$ we find the interval where this curve is concave up by finding the interval in which the 2nd derivative is positive.differentiate the curve equation with respect to x $\begin{aligned} \frac{dy}{dx} & = \frac{d}{dx} \int_{0}^x \frac{1}{1 + t + t^2} \; dt \end{aligned}$ let the function f denote be the anti-derivative of the inside expression, i.e. a function such that $(d/dx)f(x) = 1/(1 + t + t^2)$ .then use the fundamental theorem of calculus: $\begin{aligned} \frac{dy}{dx} & = \frac{d}{dx} \int_{0}^x \frac{1}{1 + t + t^2} \; dt \\& = \frac{d}{dx} \big[ f(x) - f(0) \big] & & \text{\footnotesize apply ftc} \\ & = \frac{d}{dx}f(x) - 0 \\ & = \frac{1}{x + x + x^2} & & \text{\footnotesize since $\frac{d}{dx}f(x) = \frac{1}{1 + x + x^2}$ } \end{aligned}$ differentiate again to get second derivative. we can use chain rule with 1/x as the outside function and 1 + x + x² as the inside function $\begin{aligned} \frac{d}{dx} \left( \frac{dy}{dx} \right) & = \frac{d}{dx}\left(\frac{1}{1 + x + x^2} \right) \\ \frac{d^2y}{dx^2} & = \frac{-1}{\left(1 + x + x^2\right)^2} \cdot \tfrac{d}{dx}(1 + x + x^2) \\ & = \frac{-1}{\left(1 + x + x^2\right)^2} \cdot (1 + 2x) \\ & = \frac{-(1 + 2x)}{\left(1 + x + x^2\right)^2} \end{aligned}$ find critical numbers of the second derivative. these numbers are where the 2nd deriv. is undefined or zero.where the 2nd derivative is zero: set (d²y/dx²) to equal 0 and solve for x $\begin{aligned} 0 & = \frac{-(1 + 2x)}{\left(1 + x + x^2\right)^2} \\ 0 & = -(1+2x) \\ -1 & = 2x \\ x & = -1/2 \end{aligned}$ where the 2nd derivative is undefined: if the denominator is equal to zero, the derivative will be undefeined. attempting to solve the equation 1 + x + x² = 0results in a discriminant of $b^2 - 4ac = 1^2 - 4(1)(1) = -3$ meaning that the equal 1 + x + x² = 0 has no real solutions and therefore will never equal zero.======our only critical number is x = -1/2.this forms two intervals to test the sign for: (-∞, -1/2) and (-1/2, ∞)test values into the 2nd derivative for (-∞, -1/2)if we try x = -1, we get $\begin{aligned} \left.\frac{d^2y}{dx^2}\right|_{x = -1} & = \frac{-(1+2(-1))}{\left(1+(-1)+(-1)^2\right)^2} \\ & = \frac{-(1-2)}{1} \\ & = 1 \end{aligned}$ so the since the 2nd derivative of the curve is positive on the interval (-∞, -1/2), the curve is concave up on (-∞, -1/2)test values into the 2nd derivative for (-1/2, ∞)if we try x = 0, we get $\begin{aligned} \left.\frac{d^2y}{dx^2}\right|_{x = 0} & = \frac{-(1+2(0))}{\left(1+(0)+(0)^2\right)^2} \\ & = \frac{-(1)}{1} \\ & = -1 \end{aligned}$ so the since the 2nd derivative of the curve is positive on the interval (-∞, -1/2), the curve is concave down on (-∞, -1/2).the interval on which the curve is concave up is (-∞, -1/2)

Another question on Advanced Placement (AP)

Advanced Placement (AP), 23.06.2019 05:30

In “the first seven years” by bernard malamud, how does sobel’s love of reading contrast with feld’s feelings about education?

Answers: 2

Answer

Advanced Placement (AP), 23.06.2019 11:30

Rewrite the following sentences in active voice. caution: one sentence (only one) is written in active voice. do not rewrite it just label it as being active. 1). the use of copernicus's theory was forbidden by religious leaders until 1757. 2). i am puzzled by your question. 3). the girl is frightened by horror movies; she only watches chick-flicks. 4). radium and polonium were discovered by marie curie. 5. most of the town was destroyed by a tornado. 6). these flowers were planted by the 4-h club. 7). the little boy showed his mother the bruises, cuts. and bumps on his shin. 8). pluto was discovered by clyde william tombaugh in 1930 in flagstaff, arizona. 9). the painting was purchased by mr. jones. 10). the song was performed many times by kate smith. 11). england was ruled by a woman nicknamed "bloody mary" from 1553-1558. 12). the law of universal gravitation was discovered by sir isaac newton.

Answers: 2

Answer

Advanced Placement (AP), 23.06.2019 17:00

The nervous system is responsible for our fight-or-flight response.a.autonomicb.parasympatheticc.somaticd.sympathetic select the best answer from the choices providedabcd

Answers: 2

Answer

Advanced Placement (AP), 25.06.2019 04:30

Why are radio observatories located in valleys far away from urban centers? a. to shield them from electromagnetic interference b. to avoid sound pollution c. to avoid disturbing people living in the city d. to shield them from water vapor

Answers: 1

Answer

You know the right answer?

A study found that men report high self-efficacy for both traditionally male jobs and traditionally...

Questions