Consider the cross between two different pea plants with the following genotypes: pptt x ppttp (purple flowers) is dominant over p (white flowers)t (tall plants) is dominant over t (short plants)complete the following punnett squares to determine the possible gametes for each of the above listed parent plants. (be sure to distinguish between capitals and lower case! )

Gametes of the parents would be:

PpTt : PT ; Pt ; pT ; pt

Pptt : Pt ; Pt; pt ; pt

You can do this easily using the FOIL method on each genotype. Just like in math, F stands for first; O stands for outside; I stands for inside; and L stands for last. I'll do one parent genotype and maybe you will understand how this was done:

GENOTYPE: PpTt

F- irst of each pair. P and T

P p T t

Gamete: PT

O - utside allele of the pair. P and t

P p T t

Gamete: Pt

I - inside alleles of the pair. p and T

P p T t

Gamete: pT

L-ast or end allele of each pair. p and t

P p T t

Gamete: pt

atp is used for energy.

it's d - life cycles - apex